We didn't meet as a class today due to SBAC testing, but the review sheet answers are posted below.
Test 52
1. a. 2 radical 5 b. 1/2 c. (5, 1)
2. a, radical 61 b. -5/6 c. (-2, -7.5)
3. a. 16 b. undefined c. (4, 0)
4. a radical 26 b. -1/5 c, (3.7, 5.2)
5. (x-4)2 + - 5)2 = 121
6. (7, -2); 2
7. perpendicular
8. vector
9. equals
10. (e + g)/2 , (f + h)/2
11. ( 9, 8)
12. (5, -5)
13. 5 radical 2
14. ( -15, 15)
15. graph of vector
16. a. (3, 4) b. graph
17. a. both slopes are -2/7
b. perpendicular slopes, opp. reciprocals, -2/7 and 7/2
18. same midpoint for both AC and OB; (2, 2.5)
19. midpoint of AB (8, -4)
slope of AB = 4/1; slope of PM is -1/4; opp. reciprocals so perpendicular
Test 51
1. undefined
2. 0
3. negative
4. 1/2
5. 1
6. a. 3/5; b. radical 34
7. a. -1 b. 4 radical 2
8. a. -5/2 b. 2 radical 29
9. a. 0 b. 7
10. x2 + (y + 3)2 = 36
11. (x - u)2 + (y - v)2 = a2
12. a. 2 b. (0, 0)
13. a. 1/2 b. (2, -2.5)
14. graph of circle with radius 3 and center (-2, 1); shaded inside
15. graph of line
16. a. -2/3 b. -2/3 c. 3/2
17. a. -1 b. -1 c. 1
18. 2 radical 13
19. a. all three slopes of AB, BC, and AC are = 1
b. B is between A and C (graph points to verify this)
20. a. all sides are = radical 10
b. slope of GA = 1; slope of RM = -1
slopes are opp. reciprocals so they are perpendicular lines
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